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Proof step 6 from proof prime-def-mod (previous step)

j % i = 0, i * i ≤ j, 2 ≤ j, 0 < j, 0 < i, 1 < i, 0 ≤ j, ∀ i. 1 < i ∧ i < j → ¬ i | j ⊦

User applied rule all left

And obtained the following new goals

Proof step 7:
j % i = 0, i * i ≤ j, 2 ≤ j, 0 < j, 0 < i, 1 < i, 0 ≤ j, 1 < i ∧ i < j → ¬ i | j, ∀ i. 1 < i ∧ i < j → ¬ i | j ⊦

Rule argument

pos: left 8 terms: i abort: F discard: F computed: F

Additional information

Used terms: i