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Proof step 2 from proof prime-two (previous step)

prime(2 * j) ⊦ j = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ prime(j) ↔ 2 ≤ j ∧ (∀ i. 1 < i ∧ i < j → ¬ i | j)
Proof step 4:
2 ≤ 2 * j ∧ (∀ i. 1 < i ∧ i < 2 * j → ¬ i | 2 * j) ⊦ j = 1

Rule argument

spec: int-gcd inst: name: prime-def seq: ⊦ prime(j) ↔ 2 ≤ j ∧ (∀ i. 1 < i ∧ i < j → ¬ i | j) subst: [j] → [2 * j] flags: rewrite, current

Additional information

Used terms: 2 * j