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Proof step 24 from proof square-neq-any-pos-01 (previous step)

j0 ≠ 0, j / gcd(j, j0) * j / gcd(j, j0) = j0 / gcd(j0, j) * i * j0 / gcd(j0, j), 0 < i, 0 < j, 0 < j0 ⊦ gcd(j, j0) = 1, j0 = 0, j = 0, ∃ i0. i = i0 * i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
j / gcd(j, j0) * j / gcd(j, j0) = j0 / gcd(j0, j) * i * j0 / gcd(j0, j), 0 < i, 0 < j, 0 < j0 ⊦ gcd(j, j0) = 1, j = 0, j0 = 0, ∃ i0. i = i0 * i0

Proof step 24 from proof square-neq-any-pos-01 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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