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Proof step 4 from proof square-neq-any-pos-01 (previous step)

(j * j) / gcd(j, j0) = (i * j0 * j0) / gcd(j, j0), 0 < i, 0 < j, 0 < j0, j * j = i * j0 * j0 ⊦ gcd(j, j0) = 1, ∃ i0. i = i0 * i0

User applied rule weakening

And obtained the following new goals

Proof step 5:
(j * j) / gcd(j, j0) = (i * j0 * j0) / gcd(j, j0), 0 < i, 0 < j, 0 < j0 ⊦ gcd(j, j0) = 1, ∃ i0. i = i0 * i0

Rule argument

poslist: left 5

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