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Proof step 7 from proof square-neq-any (previous step)

j * j = i * j0 * j0, i < 0, j ≠ 0 ∨ j0 ≠ 0 ⊦ j = 0, i = 0, ∃ i0. i = i0 * i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information