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Proof step 5 from proof square-neq-pos-h (previous step)

∃ i0. i * i0 = j, j * j = i * j0 * j0, gcd(j, j0) = 1, prime(i), 0 < j, 0 ≤ j0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
(i * i0) * i * i0 = i * j0 * j0, gcd(i * i0, j0) = 1, prime(i), 0 ≤ j0, 0 < i * i0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs