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Proof step 9 from proof square-neq-pos-h (previous step)

i0 * i * i0 = j0 * j0, gcd(i * i0, j0) = 1, prime(i), 0 ≤ j0, 0 < i * i0 ⊦ i = 0

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: i | j0

Additional information

Used simplifier rules: square-prime-eq: ⊦ prime(j) ∧ ¬ j | i → i * i ≠ j * j0;%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used formulas: i | j0