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Proof step 5 from proof square-neq-pos (previous step)

j * j = i * j0 * j0, prime(i), 0 < j, 0 ≤ j0 ⊦ gcd(j, j0) = 1

User applied rule cut formula

And obtained the following new goals

Proof step 6:
(j * j) / gcd(j, j0) = (i * j0 * j0) / gcd(j, j0), j * j = i * j0 * j0, prime(i), 0 < j, 0 ≤ j0 ⊦ gcd(j, j0) = 1

Rule argument

fma: (j * j) / gcd(j, j0) = (i * j0 * j0) / gcd(j, j0)

Additional information

Used simplifier rules: neqf: ⊦ i / j ≠ i / i0 → j ≠ i0; (forward) from specification int-div Used formulas: (j * j) / gcd(j, j0) = (i * j0 * j0) / gcd(j, j0)