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Proof step 12 from proof square-neq-prime (previous step)

prime(i) ∧ 0 < ~ j ∧ 0 ≤ j0 → ~ j * ~ j ≠ i * j0 * j0, j * j = i * j0 * j0, prime(i), j ≤ 0, j ≠ 0 ∨ j0 ≠ 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
j * j = i * j0 * j0, prime(i), j ≤ 0, j ≠ 0 ∨ j0 ≠ 0 ⊦ j < 0 ∧ 0 ≤ j0

Rule argument

Additional information

Used simplifier rules: neg-02: ⊦ ~ ~ i = i; from specification int-abs%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%minus-left: ⊦ ~ i * j = ~(i * j); from specification int-mult%neg: ⊦ 0 < ~ i ↔ i < 0; from specification int-abs