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Proof step 2 from proof square-neq-prime (previous step)

j * j = i * j0 * j0, prime(i), j ≠ 0 ∨ j0 ≠ 0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ prime(i) ∧ 0 < j ∧ 0 ≤ j0 → j * j ≠ i * j0 * j0
Proof step 4:
¬(prime(i) ∧ 0 < j ∧ 0 ≤ j0), j * j = i * j0 * j0, prime(i), j ≠ 0 ∨ j0 ≠ 0 ⊦

Rule argument

spec: int-gcd inst: name: square-neq-pos seq: ⊦ prime(i) ∧ 0 < j ∧ 0 ≤ j0 → j * j ≠ i * j0 * j0 subst: [j0, i, j] → [j0, i, j] flags: rewrite, current

Additional information

Used terms: j0, i, j