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Proof step 10 from proof even-add (previous step)

i % 2 ≠ 0 ∨ j % 2 ≠ 0 ⊦ i % 2 ≠ 0 ∧ j % 2 ≠ 0 ↔ odd(i) ∧ odd(j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ odd(i) ↔ i % 2 ≠ 0
Proof step 12:
i % 2 ≠ 0 ∨ j % 2 ≠ 0 ⊦ i % 2 ≠ 0 ∧ j % 2 ≠ 0 ↔ i % 2 ≠ 0 ∧ odd(j)

Rule argument

spec: inst: name: odd-def-mod seq: ⊦ odd(i) ↔ i % 2 ≠ 0 subst: [i] → [i] flags: rewrite, current

Additional information

Used terms: i