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Proof step 12 from proof even-rec (
previous step
)
j = i1 + 1, i0 + 2 = 2 * j ⊦ i0 = 2 * i1, ∃ j0. i0 = 2 * j0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 13
:
i0 + 2 = 2 * (i1 + 1) ⊦ i0 = 2 * i1, ∃ j0. i0 = 2 * j0
Rule argument
Additional information