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Proof step 7 from proof even-rec (previous step)

i0 + 2 = 2 * j ⊦ even(i0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ even(i) ↔ (∃ j. i = j + j)
Proof step 9:
i0 + 2 = 2 * j ⊦ ∃ j. i0 = j + j

Rule argument

spec: inst: name: even-def seq: ⊦ even(i) ↔ (∃ j. i = j + j) subst: [i] → [i0] flags: rewrite, current

Additional information

Used terms: i0