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Proof step 1 from proof max-01 (conclusion)

⊦ max(i, j) < j0 ↔ i < j0 ∧ j < j0

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: i < j

Additional information

Used simplifier rules: Max-right: ⊦ j < i → max(j, i) = i;%Max-left: ⊦ ¬ j < i → max(j, i) = j;%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%forward-lele: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); from specification int-abs%lst: ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i; from specification int-basic1 Used formulas: i < j