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Proof step 1 from proof min-01 (conclusion)

⊦ j0 < i ∧ j0 < j → j0 < min(i, j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
j0 < i, j0 < j, min(i, j) ≤ j0, min(i, j) < i, min(i, j) < j ⊦

Rule argument

Additional information

Used simplifier rules: forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs