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Proof step 1 from proof min-02 (conclusion)

⊦ j0 < i ∧ j0 < j → ¬ min(i, j) < j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
min(i, j) < j, min(i, j) < i, j0 < j, j0 < i, min(i, j) < j0, min(i, j) + 1 < j, min(i, j) + 1 < i ⊦

Rule argument

Additional information

Used simplifier rules: succ-01: ⊦ i +1 = i + 1; from specification int-basic2%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1