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Proof step 5 from proof min-a (previous step)

⊦ min(j, j0) = min(min(i, j), j0), i < min(j, j0)

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 6:
⊦ j < j0, min(j, j0) = min(min(i, j), j0), i < min(j, j0)

Rule argument

fma: j < j0

Additional information

Used simplifier rules: Min-left: ⊦ j < i → min(j, i) = j;%Min-right: ⊦ ¬ j < i → min(j, i) = i; Used formulas: j < j0