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Proof step 8 from proof min-a (previous step)

min(i, j) < j0 ⊦ j0 = min(min(i, j), j0), j < j0, i < j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
min(i, j) < j0, min(i, j) < j, min(i, j) < i ⊦ j0 = min(i, j), j < j0, i < j0

Rule argument

Additional information

Used simplifier rules: Min-left: ⊦ j < i → min(j, i) = j;%lf-07: ⊦ ¬ i < i0 ∧ j < i0 → j < i; (forward) from specification int-basic1