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Proof step 1 from proof min-abs-zero-01 (conclusion)

⊦ ¬ min(abs(i), abs(j)) < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
min(abs(i), abs(j)) < 0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs