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Proof step 5 from proof not-odd-ex (previous step)

⊦ ∃ j. i = 2 * j, ∃ j. i = 2 * j + 1

User applied rule insert spec-lemma

And obtained the following new goals

Rule argument

spec: int-mult inst: name: ex-two seq: ⊦ (∃ j. i = 2 * j) ∨ (∃ j. i = 2 * j + 1) subst: [i] → [i] flags:

Additional information

Used terms: i