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Proof step 13 from proof odd-add (previous step)

(¬ even(i) ∨ ¬ even(j)) ∧ (even(i) ∨ even(j)) ⊦ ¬ even(i) ∧ even(j) ∨ even(i) ∧ ¬ even(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information