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Proof step 16 from proof abs-ls-same-01 (previous step)

j < 0 ⊦ abs(i) * j < i ↔ ¬ i ≤ 0 ∨ i ≠ 0 ∧ j ≠ ~1

User applied rule cut formula

And obtained the following new goals

Proof step 17:
j = ~1, j < 0 ⊦ abs(i) * j < i ↔ ¬ i ≤ 0 ∨ i ≠ 0 ∧ j ≠ ~1
Proof step 19:
j < 0 ⊦ j = ~1, abs(i) * j < i ↔ ¬ i ≤ 0 ∨ i ≠ 0 ∧ j ≠ ~1

Rule argument

fma: j = ~1

Additional information

Used formulas: j = ~1