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Proof step 4 from proof abs-ls-same-01 (
previous step
)
⊦ abs(i) * j < i ↔ 0 < i ∧ j ≤ 0 ∨ i < 0 ∧ ¬ ~1 ≤ j
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 5
:
⊦ ¬ i < j ↔ j ≤ i
Proof step 6
:
⊦ abs(i) * j < i ↔ 0 < i ∧ j ≤ 0 ∨ ¬ 0 ≤ i ∧ ¬ ~1 ≤ j
Rule argument
spec: int-abs inst: name: lels seq: ⊦ ¬ i < j ↔ j ≤ i subst: [j, i] → [0, i] flags: rewrite
Additional information
Used terms: 0, i