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Proof step 8 from proof abs-ls-same-01 (previous step)

⊦ abs(i) * j < i ↔ 0 < i ∧ ¬ 0 < j ∨ ¬ 0 ≤ i ∧ ¬ ~1 ≤ j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ ¬ i < j ↔ j ≤ i
Proof step 10:
⊦ abs(i) * j < i ↔ ¬ i ≤ 0 ∧ ¬ 0 < j ∨ ¬ 0 ≤ i ∧ ¬ ~1 ≤ j

Rule argument

spec: int-abs inst: name: lels seq: ⊦ ¬ i < j ↔ j ≤ i subst: [j, i] → [i, 0] flags: rewrite

Additional information

Used terms: i, 0