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Proof step 4 from proof associativity (previous step)

∀ i, j. i * j * j1 = (i * j) * j1 ⊦ i * j * j1 -1 = (i * j) * j1 -1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 5:
j1 = i0 +1, ∀ i, j. i * j * j1 = (i * j) * j1 ⊦ i * j * i0 = (i * j) * i0

Rule argument

spec: int-basic1 inst: name: elim-pred seq: ⊦ i = j -1 ↔ j = i +1 subst: [j, i] → [j1, i0] flags:

Additional information

Used simplifier rules: ⊦ i = j -1 ↔ j = i +1; (elim) Used terms: j1, i0