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Proof step 6 from proof associativity (previous step)

∀ i1, j0. i1 * j0 * (i0 + 1) = (i1 * j0) * (i0 + 1) ⊦ i * j * i0 = (i * j) * i0

User applied rule all left

And obtained the following new goals

Proof step 7:
i * j * (i0 + 1) = (i * j) * (i0 + 1), ∀ i1, j0. i1 * j0 * (i0 + 1) = (i1 * j0) * (i0 + 1) ⊦ i * j * i0 = (i * j) * i0

Rule argument

pos: left 1 terms: i, j abort: F discard: F computed: F

Additional information

Used terms: i, j