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Proof step 9 from proof associativity (previous step)

i * (j * i0 + j * 1) = (i * j) * (i0 + 1), ∀ i1, j0. i1 * j0 * (i0 + 1) = (i1 * j0) * (i0 + 1) ⊦ i * j * i0 = (i * j) * i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: one: ⊦ 1 * i = i;%commutativity: ⊦ i * j = j * i;