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Proof step 1 from proof eq-neg (conclusion)

⊦ i < 0 → (i * j = i * j0 ↔ j = j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i * j = i * j0, i < 0 ⊦ j = j0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs