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Proof step 15 from proof eq-nonzero (previous step)

0 < i, i * j < i * j0, i * j = i * j0, 0 < i ⊦ j = j0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 3 flags: discard

Additional information

Used simplifier rules: ls-pos: ⊦ 0 < i → (i * j < i * j0 ↔ j < j0);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;%irref: ⊦ ¬ i < i; from specification int-basic1