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Proof step 16 from proof eq-nonzero (previous step)

i * j = i * j0, 0 < i ⊦ j < j0, j = j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
i * j = i * j0, 0 < i, j0 < j ⊦

Rule argument

Additional information

Used simplifier rules: ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1