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Proof step 6 from proof eq-nonzero (previous step)

i < 0, i * j0 < i * j, i < 0, i * j = i * j0 ⊦ i = 0, j = j0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 4 flags: discard

Additional information

Used simplifier rules: ls-neg: ⊦ i < 0 → (i * j < i * j0 ↔ j0 < j);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;%irref: ⊦ ¬ i < i; from specification int-basic1