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Proof step 4 from proof eq-one-neg (previous step)

~(i * j) = 1, i * j = ~1 ⊦ abs(j) = 1 ∧ j + i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ ~ i * j = ~(i * j)
Proof step 6:
~ i * j = 1, i * j = ~1 ⊦ abs(j) = 1 ∧ j + i = 0

Rule argument

spec: int-mult inst: name: minus-left seq: ⊦ ~ i * j = ~(i * j) subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i