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Proof step 1 from proof eq-pos-01 (conclusion)

⊦ 0 < j → (i * j = i0 * j ↔ i = i0)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: eq-pos: ⊦ 0 < i → (i * j = i * j0 ↔ j = j0);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;