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Proof step 27 from proof exdivmod (previous step)

i + i0 * j + j0 = 0, 0 ≤ j0, 0 ≤ i0, j0 < j, i ≤ 0, i < 0, 0 < j ⊦ ∃ i1, j1. i = i1 * j + j1 ∧ abs(j1) < j

User applied rule exists right

And obtained the following new goals

Proof step 28:
i + i0 * j + j0 = 0, 0 ≤ j0, 0 ≤ i0, j0 < j, i ≤ 0, i < 0, 0 < j ⊦ i = (~ i0 - 1) * j + (j - j0) ∧ abs(j - j0) < j, ∃ i1, j1. i = i1 * j + j1 ∧ abs(j1) < j

Rule argument

pos: right 1 terms: ~ i0 - 1, j - j0 abort: F discard: F computed: F

Additional information

Used terms: ~ i0 - 1, j - j0