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Proof step 2 from proof le-neg (previous step)

i < 0 ⊦ i * j ≤ i * i0 ↔ i0 ≤ j

User applied rule case distinction

And obtained the following new goals

Proof step 3:
i * j ≤ i * i0, i < 0 ⊦ i0 ≤ j

Rule argument

pos: right 1

Additional information

Used simplifier rules: ls-neg: ⊦ i < 0 → (i * j < i * j0 ↔ j0 < j);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%lenls: ⊦ i ≤ j → ¬ j < i; from specification int-abs