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Proof step 1 from proof le-pos (conclusion)

⊦ 0 < i → (i * j ≤ i * i0 ↔ j ≤ i0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i ⊦ i * j ≤ i * i0 ↔ j ≤ i0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs