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Proof step 3 from proof le-pos (previous step)

i * j ≤ i * i0, 0 < i ⊦ j ≤ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i * j ≤ i * i0, 0 < i, i0 < j ⊦

Rule argument

Additional information

Used simplifier rules: lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs