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Proof step 3 from proof ls-add (previous step)

i0 * j + j1 < j, j1 < j, 0 ≤ j1, 0 < j ⊦ i0 ≤ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i0 * j + j1 < j, j1 < j, 0 ≤ j1, 0 < j, 0 < i0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs