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Proof step 4 from proof ls-pos (previous step)

0 < i, ∀ i, j0. 0 < i → (i * j1 < i * j0 ↔ j1 < j0) ⊦ i * j1 + i < i * j0 ↔ j1 + 1 < j0

User applied rule all left

And obtained the following new goals

Proof step 5:
0 < i, 0 < i → (i * j1 < i * j0 -1 ↔ j1 < j0 -1), ∀ i, j0. 0 < i → (i * j1 < i * j0 ↔ j1 < j0) ⊦ i * j1 + i < i * j0 ↔ j1 + 1 < j0

Rule argument

pos: left 2 terms: i, j0 -1 abort: F discard: F computed: F

Additional information

Used terms: i, j0 -1