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Proof step 1 from proof ls-same-05 (conclusion)

⊦ 1 < i → (j * i < i ↔ j < 1)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ls-same: ⊦ 0 < i → (i * j < i ↔ j < 1);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;%zero-gels-04: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%lsone: ⊦ i < 1 ↔ i ≤ 0; from specification int-abs