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Proof step 3 from proof minus-left (previous step)

⊦ (0 - i) * j = ~(i * j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ 0 - i = ~ i
Proof step 5:
⊦ (0 - i) * j = 0 - i * j

Rule argument

spec: int-abs inst: name: neg-06 seq: ⊦ 0 - i = ~ i subst: [i] → [i * j] flags: rewrite

Additional information

Used terms: i * j