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Proof step 10 from proof mod-neq (previous step)

¬ i < 0, i * j = i * j0 + j1, abs(j1) < i ⊦ j1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
i * j = i * j0 + j1, abs(j1) < i, 0 ≤ i ⊦ j1 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs