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Proof step 2 from proof modeqp-03 (
previous step
)
i * j + j0 = i0 * j + j1, j0 ≤ 0, abs(j0) < j, j1 ≤ 0, abs(j1) < j ⊦ i = i0 ∧ j0 = j1
Lemma
modeqp-01