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Proof step 2 from proof modeqp-copied (previous step)

i * j + j0 = i0 * j + j1, j0 < j, j1 < j, 0 ≤ j0, 0 ≤ j1, 0 < j ⊦ i = i0 ∧ j0 = j1

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: i = i0

Additional information

Used simplifier rules: add-in: ⊦ i + j = i + i0 ↔ j = i0; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i = i0