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Proof step 1 from proof modlep-04 (conclusion)

j * i + j0 ≤ j * i0 + j1, j0 ≤ 0, j1 ≤ 0, abs(j0) < j, abs(j1) < j ⊦ i ≤ i0

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
j * i + j0 ≤ j * i0 + j1, 0 ≤ j0, j0 < j, abs(j1) < j ⊦ i ≤ i0
Proof step 3:
j * i + j0 ≤ j * i0 + j1, j0 ≤ 0, j1 ≤ 0, abs(j0) < j, abs(j1) < j ⊦ j * i + abs(j1) ≤ j * i0 + abs(j0) ∧ 0 ≤ abs(j1) ∧ abs(abs(j0)) < j, i ≤ i0

Rule argument

spec: int-mult inst: name: modlep-03 seq: j * i + j0 ≤ j * i0 + j1, 0 ≤ j0, j0 < j, abs(j1) < j ⊦ i ≤ i0 subst: [j, i, j0, i0, j1] → [j, i, abs(j1), i0, abs(j0)] flags: current, []

Additional information

Used terms: j, i, abs(j1), i0, abs(j0)