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Proof step 1 from proof mods-nls (conclusion)

⊦ 0 < i → ¬ i * abs(j) < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i * abs(j) < j, 0 < i ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs