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Proof step 1 from proof modzero (conclusion)

⊦ 0 < i ∧ abs(j0) < j → ¬ i * j + j0 < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i * j + j0 < i, i * j + j0 < 0, abs(j0) < j, 0 < i, (i * j + j0) + 1 < i ⊦

Rule argument

Additional information

Used simplifier rules: succ-01: ⊦ i +1 = i + 1; from specification int-basic2%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs