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Proof step 1 from proof mult-gt-both (conclusion)

⊦ 0 ≤ i ∧ 0 ≤ j ∧ 0 ≤ i1 ∧ 0 ≤ j1 ∧ i < i1 ∧ j < j1 → i * j < i1 * j1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs