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Proof step 22 from proof noeth-modlep (previous step)

0 < j2, j0 < j2, 0 ≤ j0, i0 < i, j ≤ j2, j0 < j, j * i ≤ j * i0 + j0, 0 < j, ∀ j, i, i0, j0. abs(j) < j2 → abs(j) * i ≤ abs(j) * i0 + j0 ∧ 0 ≤ j0 ∧ j0 < abs(j) → i ≤ i0 ⊦

User applied rule all left

And obtained the following new goals

Proof step 23:
0 < j2, j0 < j2, 0 ≤ j0, i0 < i, j ≤ j2, j0 < j, j * i ≤ j * i0 + j0, 0 < j, abs(j - 1) < j2 → abs(j - 1) * i ≤ abs(j - 1) * i0 + j0 ∧ 0 ≤ j0 ∧ j0 < abs(j - 1) → i ≤ i0 ⊦

Rule argument

pos: left 9 terms: j - 1, i, i0, j0 abort: F discard: T computed: F

Additional information

Used terms: j - 1, i, i0, j0