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Proof step 24 from proof noeth-modlep (previous step)

0 < j2, j0 < j2, 0 ≤ j0, i0 < i, j ≤ j2, j0 < j, j * i ≤ j * i0 + j0, 0 < j ⊦ (j - 1) * i ≤ (j - 1) * i0 + j0 ∧ j0 + 1 < j

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 25:
j = i1 + 1, 0 < j2, j0 < j2, 0 ≤ j0, i0 < i, j ≤ j2, j0 < j, j * i ≤ j * i0 + j0, 0 < j ⊦ i1 * i ≤ i1 * i0 + j0 ∧ j0 + 1 < j

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, 1, i1] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, 1, i1